2y(y+2)=2(y^2-7)+2

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Solution for 2y(y+2)=2(y^2-7)+2 equation: 


Simplifying
2y(y + 2) = 2(y2 + -7) + 2

Reorder the terms:
2y(2 + y) = 2(y2 + -7) + 2
(2 * 2y + y * 2y) = 2(y2 + -7) + 2
(4y + 2y2) = 2(y2 + -7) + 2

Reorder the terms:
4y + 2y2 = 2(-7 + y2) + 2
4y + 2y2 = (-7 * 2 + y2 * 2) + 2
4y + 2y2 = (-14 + 2y2) + 2

Reorder the terms:
4y + 2y2 = -14 + 2 + 2y2

Combine like terms: -14 + 2 = -12
4y + 2y2 = -12 + 2y2

Add '-2y2' to each side of the equation.
4y + 2y2 + -2y2 = -12 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
4y + 0 = -12 + 2y2 + -2y2
4y = -12 + 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
4y = -12 + 0
4y = -12

Solving
4y = -12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '4'.
y = -3

Simplifying
y = -3

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